这个问题，使得人们仿佛又回到了字符界面的时代。

问题链接：。

题意简述：学生成绩有关数据的增删统计等（具体内容参见原问题）。

问题分析：使用一个结构类型数组存储数据，对其中数据进行操作。字符时代的软件似乎就是这样，只是少了用文件来存储最终的结果。

程序说明：（略）。

AC的C语言程序如下：

/* UVA12412 A Typical Homework (a.k.a Shi Xiong Bang Bang Mang) */#include 
    
     #include 
     
      #include 
      
       #define MAXN 100#define MAXLEN1 10#define MAXLEN2 20#define EPS 1e-5struct student {    char sid[MAXLEN1+1];    int cid;    char name[MAXLEN2+1];    int score[5];    int removed;} all[MAXN+1];int scount;void output_menu(){    printf("Welcome to Student Performance Management System (SPMS).\n\n");    printf("1 - Add\n");    printf("2 - Remove\n");    printf("3 - Query\n");    printf("4 - Show ranking\n");    printf("5 - Show Statistics\n");    printf("0 - Exit\n\n");}void add(){    int dflag, i;    for(;;) {        printf("Please enter the SID, CID, name and four scores. Enter 0 to finish.\n");        struct student in;        scanf("%s", in.sid);        if(strcmp(in.sid, "0") == 0)            break;        scanf("%d", &in.cid);        scanf("%s", in.name);        scanf("%d", &in.score[1]);        scanf("%d", &in.score[2]);        scanf("%d", &in.score[3]);        scanf("%d", &in.score[4]);        dflag = 0;        for(i=0; i
       
         t)            high++;    return high + 1;}void queryremove(int flag){    char s[MAXLEN1+1];    int i;    for(;;) {        printf("Please enter SID or name. Enter 0 to finish.\n");        scanf("%s", s);        if(strcmp(s, "0") == 0)            break;        int rcount = 0;        for(i=0; i
        
         = 60)                count1++;            else                count2++;        }    }    printf("Average Score: %.2f\n", count1+count2 == 0 ? 0 : sum*1.0/(count1+count2)+EPS);    printf("Number of passed students: %d\n", count1);    printf("Number of failed students: %d\n", count2);    printf("\n");}void statistics(){    int id, i, j;    printf("Please enter class ID, 0 for the whole statistics.\n");    scanf("%d", &id);    printf("Chinese\n");    output_score(id, 1);    printf("Mathematics\n");    output_score(id, 2);    printf("English\n");    output_score(id, 3);    printf("Programming\n");    output_score(id, 4);    printf("Overall:\n");    int okcount[5];    memset(okcount, 0, sizeof(okcount));    for(i=0; i
         
          = 60) ok++; okcount[ok]++; } } printf("Number of students who passed all subjects: %d\n", okcount[4]); printf("Number of students who passed 3 or more subjects: %d\n", okcount[3]+okcount[4]); printf("Number of students who passed 2 or more subjects: %d\n", okcount[2]+okcount[3]+okcount[4]); printf("Number of students who passed 1 or more subjects: %d\n", okcount[1]+okcount[2]+okcount[3]+okcount[4]); printf("Number of students who failed all subjects: %d\n", okcount[0]); printf("\n");}int main(void){ int choice; scount = 0; for(;;) { output_menu(); scanf("%d", &choice); if(choice == 1) add(); else if(choice == 2) queryremove(0); else if(choice == 3) queryremove(1); else if(choice == 4) printf("Showing the ranklist hurts students' self-esteem. Don't do that.\n"); else if(choice == 5) statistics(); else if(choice == 0) break; } return 0;}